Ford India IT Related Job in Chennai!! BE, B.Tech Can Apply!! The famous motor company FIPL – Ford India Pvt Ltd revealed a notice regard the job opening for the post of J2EE-A2F-Developer. This is a marvelous opportunity to work in such a big organization. Interested candidates with profession in IT can apply for this post by using the details shared below.
Ford Job 2022 Details
Name of the Company | FIPL – Ford India Pvt Ltd |
Name of the Job | J2EE-A2F-Developer |
Auto req ID | 60133BR |
Location | Chennai |
Status | Notice Out |
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Ford India Recruitment 2022 Qualification
Candidates should have the degree at B.E or B.Tech to apply for this J2EE-A2F-Developer post in Ford.
Ford India Recruitment 2022 Eligibility Criteria
- The candidates for this J2EE-A2F-Developer job in Ford must have the 4+ years of IT experience and Strong in J2EE development.
- He/ She have knowledge and experience in SQL Server Database, JPA and developing backend with Springboot and/or Spring Framework
- Applicants should have an experience in developing frontend with Angular 8/9/10/11, Rest Template, RESTful services, CI/CD tools like GIT, GITHUB, JENKINS and some others.
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How to Apply For This Ford Job
- Enter the official website of the Ford.
- Search and find the tag named as job search and click it.
- In the search bar enter the job title, job category, or keywords related to the job you search for.
- The appropriate job notification will appear on the screen.
- Scroll the page to bottom and touch the link “Apply to Job”.
- This will lead to you to the login page.
- Register yourself there and create an account for you if you are new to Ford registration or sign in to your account.
- Registration process is completed
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60133BR is the Auto Req ID for this job in Ford.
Candidates should have the degree at B.E or B.Tech to apply for this J2EE-A2F-Developer post in Ford.
The selected candidate to this J2EE-A2F-Developer post job in Ford will be work at Chennai.